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U. Glaeser

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db(T( )/G O)<br />

π ω<br />

ph(T( )/ )<br />

ω<br />

FIGURE 10.5 PLL loop gain magnitude and phase (without C 2).<br />

The closed-loop response can be derived from the open-loop response by considering the feedback<br />

signal. In the closed-loop system, the output phase, P O(s), is related to the input phase, P I(s), by<br />

© 2002 by CRC Press LLC<br />

P O(s) = (P I(s) − P O(s)/N) ⋅ H(s)<br />

where N is the feedback clock divider value. The closed-loop response is then given by<br />

or, equivalently, by<br />

200<br />

150<br />

100<br />

50<br />

0<br />

|<br />

|<br />

|<br />

|<br />

|<br />

-50<br />

-100 | | | | |||||| | | | |||||| | | | |||||| | | | |||||| | | | |||||| | | | |||||| | | | |||||| | | | ||||||<br />

10-4 10-3 10-2 10-1 100 101 102 103 104 0.0<br />

-0.2<br />

-0.4<br />

-0.6<br />

-0.8<br />

|<br />

|<br />

|<br />

|<br />

|<br />

|<br />

|<br />

where ζ, defined as the damping factor, is given by<br />

•R•C<br />

•R•C<br />

-1.0 | | | | |||||| | | | |||||| | | | |||||| | | | |||||| | | | |||||| | | | |||||| | | | |||||| | | | ||||||<br />

10-4 10-3 10-2 10-1 100 101 102 103 104 |<br />

PO()�P s I s<br />

PO ()�P s I s<br />

ζ = 1�2 ⋅ (1/ N ⋅ I CH ⋅ K V ⋅ R 2 ⋅ C) 0.5<br />

and ω N, defined as the loop bandwidth (rad/s), is given by<br />

ω<br />

ω N = 2 ⋅ ζ �(R ⋅ C)<br />

The loop bandwidth and damping factor completely characterize the closed-loop response. The PLL<br />

is critically damped with a damping factor of one and overdamped with damping factors greater than one.<br />

Treating the PLL as a standard second order system makes it much easier to analyze. The time domain<br />

impulse, step, and ramp responses are easily derived from the frequency domain closed-loop response.<br />

Equations for these responses are summarized in Table 10.2. The peak values of these responses are very<br />

useful in estimating the amount of frequency overshoot and the amount of supply and substrate noise<br />

ω<br />

() = 1�( 1/N + s�H() s)<br />

= N⋅1+ s⋅ C⋅ R/<br />

1 s C R s 2 ( + ⋅ ⋅ + / ( ICH/C ⋅ KV/N) )<br />

() = N⋅( 1 + 2 ⋅ζ⋅( s/ω N)�<br />

( 1 2 ζ ( s/ω N)<br />

( s/ω N)<br />

2 +<br />

⋅ ⋅ + )

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