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Molecular Biology of the Cell by Bruce Alberts, Alexander Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter by by Bruce Alberts, Alexander Johnson, Julian Lewis, David Morg

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170 Chapter 3: Proteins

Problems

Which statements are true? Explain why or why not.

3–1 Each strand in a β sheet is a helix with two amino

acids per turn.

3–2 Intrinsically disordered regions of proteins can be

identified using bioinformatic methods to search genes for

encoded amino acid sequences that possess high hydrophobicity

and low net charge.

3–3 Loops of polypeptide that protrude from the surface

of a protein often form the binding sites for other molecules.

3–4 An enzyme reaches a maximum rate at high substrate

concentration because it has a fixed number of

active sites where substrate binds.

3–5 Higher concentrations of enzyme give rise to a

higher turnover number.

3–6 Enzymes that undergo cooperative allosteric transitions

invariably consist of symmetric assemblies of multiple

subunits.

3–7 Continual addition and removal of phosphates

by protein kinases and protein phosphatases is wasteful

of energy—since their combined action consumes ATP—

but it is a necessary consequence of effective regulation by

phosphorylation.

Discuss the following problems.

3–8 Consider the following statement. “To produce

one molecule of each possible kind of polypeptide chain,

300 amino acids in length, would require more atoms than

exist in the universe.” Given the size of the universe, do you

suppose this statement could possibly be correct? Since

counting atoms is a tricky business, consider the problem

from the standpoint of mass. The mass of the observable

universe is estimated to be about 10 80 grams, give or take

an order of magnitude or so. Assuming that the average

mass of an amino acid is 110 daltons, what would be the

mass of one molecule of each possible kind of polypeptide

chain 300 amino acids in length? Is this greater than the

mass of the universe?

3–9 A common strategy for identifying distantly related

homologous proteins is to search the database using a short

signature sequence indicative of the particular protein

function. Why is it better to search with a short sequence

than with a long sequence? Do you not have more chances

for a “hit” in the database with a long sequence?

3–10 The so-called kelch motif consists of a fourstranded

β sheet, which forms what is known as a β propeller.

It is usually found to be repeated four to seven times,

forming a kelch repeat domain in a multidomain protein.

One such kelch repeat domain is shown in Figure Q3–1.

Would you classify this domain as an “in-line” or “plug-in”

type domain?

β6

β5

β4

β3

C

N

Figure Q3–1 The

kelch repeat domain of

galactose oxidase from

D. dendroides (Problem

3–10). The seven individual

β propellers are color

coded and labeled. The

N- and C-termini are

indicated by N and C.

3–11 Titin, which has a molecular weight of about

3 × 10 6 , is the largest polypeptide yet described. Titin

molecules Problems extend p3.06/3.06 from muscle thick filaments to the

Z disc; they are thought to act as springs to keep the thick

filaments centered in the sarcomere. Titin is composed of a

large number of repeated immunoglobulin (Ig) sequences

of 89 amino acids, each of which is folded into a domain

about 4 nm in length (Figure Q3–2A).

You suspect that the springlike behavior of titin is

caused by the sequential unfolding (and refolding) of individual

Ig domains. You test this hypothesis using the atomic

force microscope, which allows you to pick up one end of

a protein molecule and pull with an accurately measured

force. For a fragment of titin containing seven repeats of the

Ig domain, this experiment gives the sawtooth force-versus-extension

curve shown in Figure Q3–2B. If the experiment

is repeated in a solution of 8 M urea (a protein denaturant),

the peaks disappear and the measured extension

becomes much longer for a given force. If the experiment

is repeated after the protein has been cross-linked by treatment

with glutaraldehyde, once again the peaks disappear

but the extension becomes much smaller for a given force.

(A)

(B)

force (pN)

400

300

200

100

0

N

β7

Figure Q3–2 Springlike behavior of titin (Problem 3–11). (A) The

structure of an individual Ig domain. (B) Force in piconewtons versus

extension in nanometers obtained by atomic force microscopy.

β1

β2

0 50 100 150 200

extension (nm)

C

Problems p3.12/3.11

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