13.09.2022 Views

Molecular Biology of the Cell by Bruce Alberts, Alexander Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter by by Bruce Alberts, Alexander Johnson, Julian Lewis, David Morg

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

510 Chapter 8: Analyzing Cells, Molecules, and Systems

assess the biological impact of any interaction in the cell, we need to know in

precise terms how the molecules interact, how they catalyze reactions, and, most

importantly, how the behaviors of the molecules change over time. If a cartoon

shows that protein A activates protein B, for example, we cannot judge the importance

of this relationship without quantitative details about the concentrations,

affinities, and kinetic behaviors of proteins A and B.

Let us begin by defining two different types of regulatory interaction in our

cartoons: one designating inhibition and the other designating activation. If the

protein product of gene X is a transcription repressor that inhibits the expression

of gene Z, we depict the relationship as a red bar-headed line ( ) drawn between

genes X and Z (Figure 8–71). If the protein product of gene Y is a transcription

activator that induces the expression of gene Z, then a green arrow ( ) is drawn

between genes Y and Z.

The regulation of one gene’s expression by another is more complicated than

a single arrow connecting them, and a complete understanding of this regulation

requires that we tease apart the underlying biochemical processes. Figure 8–72A

sketches some of the biochemical steps in the activation of gene expression by a

transcription activator. A gene encoding the activator, designated as gene A, will

produce its product, protein A, via an RNA intermediate. This protein A will then

bind to p X , the regulatory promoter of gene X, to form the complex A:p X . Once the

A:p X complex forms, it stimulates the production of an RNA transcript that is subsequently

translated to produce protein X.

We will focus here on the binding interaction that lies at the heart of this regulatory

system: the interaction between protein A and the promoter p X . Any molecule

of protein A that is bound to p X can also dissociate from it. The steps represented

by the green activation arrow in Figure 8–72A include both the binding of

A to p X and the dissociation of the complex A:p X to re-form A and p X , as illustrated

GENE X

GENE Z

GENE Y

GENE Z

Figure 8–71 Diagrams that summarize

biochemical relationships. Here, a simple

cartoon indicates MBoC6 that n8.600/8.72 gene X represses

gene Z (left) whereas gene Y activates gene

Z (right).

SUDDEN

ACTIVATING

INPUT

A + p X

k on

A:p X

k off

GENE A

DNA

rate of complex formation = k on [A][p X ]

RNA

rate of complex dissociation = k off [A:p X ]

(A)

A

A

promoter

(p X )

transcription

activator protein

GENE X

X

DNA

RNA

protein

(B)

at steady state:

k on [A][p X ] = k off [A:p X ]

k

[A:p X ] = on

[A][p X ] = K[A][p X ] Equation 8–1

k off

(C)

[p T X ] = [p X ] + [A:p X ]

substituting [p X ] from the above equation into

Equation 8–1 yields:

[A:p X ] = K[A]([p T X ] – [A:p X ])

[A:p X ](1 + K[A]) = K[A][p T X ]

K[A]

[A:p X ] = [pT

X ]

1 + K[A]

(D)

(E)

Equation 8–2

[A:p

bound fraction = X ] K[A] =

Equation 8–3

[p T

X ] 1 + K[A]

Figure 8–72 A simple transcriptional

interaction. (A) Genes A and X each

produce a protein, with the product of

gene A serving as a transcription activator

to stimulate expression of gene X. As

indicated by the green arrow, stimulation

depends in part on the binding of protein

A to the promoter region of gene X,

designated as p X . (B) The binding of protein

A to the gene promoter is determined

by the concentrations of the two binding

partners (denoted as [A] and [p X ], in units

of mol/liter, or M), the association rate

constant k on (in units of sec –1 M –1 ), and

the dissociation rate constant k off (in units

of sec –1 ). (C) At steady state, the rates of

association and dissociation are equal, and

the concentration of the bound complex is

determined by Equation 8–1, in which the

two rate constants are combined in the

equilibrium constant K. (D) Equation 8–2

can be derived to calculate the steadystate

concentration of bound complex at a

known total concentration of the promoter

[p X

T ]. (E) Rearrangement of Equation

8–2 yields Equation 8–3, which allows

calculation of the fraction of promoter p X

that is occupied by protein A.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!