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Molecular Biology of the Cell by Bruce Alberts, Alexander Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter by by Bruce Alberts, Alexander Johnson, Julian Lewis, David Morg

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CHAPTER 5 END-OF-CHAPTER PROBLEMS

297

(A)

(B)

50 µm

Figure Q5–2 Autoradiographic investigation of DNA replication in cultured

cells (Problem 5–11). (A) Addition of 3 H-labeled thymidine immediately

after release from the synchronizing block. (B) Addition of 3 H-labeled

thymidine 30 minutes after release from the synchronizing block.

Problems p5.15/5.11/Q5.2

bubbles, the daughter duplexes lie side by side and cannot

be distinguished from each other.

You pretreat the cells to synchronize them at the

beginning of S phase. In the first experiment, you release

the synchronizing block and add 3 H-thymidine immediately.

After 30 minutes, you wash the cells and change the

medium so that the total concentration of thymidine is the

same as it was, but only one-third of it is radioactive. After

an additional 15 minutes, you prepare DNA for autoradiography.

The results of this experiment are shown in Figure

Q5–2A. In the second experiment, you release the synchronizing

block and then wait 30 minutes before adding

3 H-thymidine. After 30 minutes in the presence of 3 H-thymidine,

you once again change the medium to reduce the

concentration of radioactive thymidine and incubate the

cells for an additional 15 minutes. The results of the second

experiment are shown in Figure Q5–2B.

A. Explain why, in both experiments, some regions of

the tracks are dense with silver grains (dark), whereas others

are less dense (light).

B. In the first experiment, each track has a central

dark section with light sections at each end. In the second

experiment, the dark section of each track has a light section

at only one end. Explain the reason for this difference.

C. Estimate the rate of fork movement (μm/min) in

these experiments. Do the estimates from the two experiments

agree? Can you use this information to gauge how

long it would take to replicate the entire genome?

5–12 If you compare the frequency of the sixteen possible

dinucleotide sequences in the E. coli and human

genomes, there are no striking differences except for one

dinucleotide, 5ʹ-CG-3ʹ. The frequency of CG dinucleotides

in the human genome is significantly lower than in E. coli

and significantly lower than expected by chance. Why do

you suppose that CG dinucleotides are underrepresented

in the human genome?

5–13 With age, somatic cells are thought to accumulate

genomic “scars” as a result of the inaccurate repair of double-strand

breaks by nonhomologous end joining (NHEJ).

Estimates based on the frequency of breaks in primary

human fibroblasts suggest that by age 70, each human

somatic cell may carry some 2000 NHEJ-induced mutations

due to inaccurate repair. If these mutations were

distributed randomly around the genome, how many protein-coding

genes would you expect to be affected? Would

you expect cell function to be compromised? Why or why

not? (Assume that 2% of the genome—1.5% protein-coding

and 0.5% regulatory—is crucial information.)

5–14 Draw the structure of the double Holliday junction

that would result from strand invasion by both ends of the

broken duplex into the intact homologous duplex shown

in Figure Q5–3. Label the left end of each strand in the Holliday

junction 5ʹ or 3ʹ so that the relationship to the parental

and recombinant duplexes is clear. Indicate how DNA

synthesis would be used to fill in any single-strand gaps in

your double Holliday junction.

5′ 3′

5′ 3′

Figure Q5–3 A broken duplex with

single-strand tails ready to invade

an intact homologous duplex

(Problem 5–14).

5–15 In addition to correcting DNA mismatches, the

mismatch repair system functions to prevent homologous

recombination Problems p5.39/5.27/Q5.2/Q5.3

from taking place between similar but not

identical sequences. Why would recombination between

similar, but nonidentical sequences pose a problem for

human cells?

5–16 Cre recombinase is a site-specific enzyme that

catalyzes recombination between two LoxP DNA sites.

Cre recombinase pairs two LoxP sites in the same orientation,

breaks both duplexes at the same point in each LoxP

site, and joins the ends with new partners so that each

LoxP site is regenerated, as shown schematically in Figure

Q5–4A. Based on this mechanism, predict the arrangement

of sequences that will be generated by Cre-mediated

site-specific recombination for each of the two DNAs

shown in Figure Q5–4B.

(A)

BREAK

REJOIN

(B)

a b c d a b c d

Figure Q5–4 Cre recombinase-mediated site-specific recombination

(Problem 5–16). (A) Schematic representation of Cre/LoxP site-specific

recombination. The LoxP sequences in the DNA are represented by

triangles that are colored so that the site-specific recombination event

can be followed more readily. In reality their DNA sequences

are identical. (B) DNA substrates containing two arrangements of

LoxP sites.

Problems p5.43/5.32/Q5.4

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