12.07.2015 Views

Numerical Mathematics - A Collection of Solved Problems

Numerical Mathematics - A Collection of Solved Problems

Numerical Mathematics - A Collection of Solved Problems

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

64 OPŠTA TEORIJA ITERATIVNIH PROCESAIskoristimo sada navedenu teoremu u zadatku 3.2.3 za ubrzavanje konvergencijeprocesa (3). Dakle, iterativni proces x k+1 = F(x k ), gde je(4) F(x) = x − x − G(x)1 − G ′ (x) ,ima red konvergencije najmanje 2. S obzirom da jeG ′ (x) = 1 −na osnovu (4) dobijamo`f(x) + (x − α) f ′ (x)´(f(x) − f(α)) − f(x)f ′ (x)(x − α)(f(x) − f(α)) 2 ,f(x)(f(x) − f(α))(x − α)F(x) = x −(f(x) + (x − α) f ′ (x))(f(x) − f(α)) − f(x)f ′ (x)(x − α)f(x) − f(α)= x − „1 + (x − α) f ′ «(x) f(x) − f(α)− ff(x) x − α′ (x)f(x) − f(α)= x −f(x) − f(α)− f(α)f ′ .(x)x − α f(x)Najzad, s obzirom na (2), imamo(5) F(x) = x −g(x)(x − α)g(x) − h(x)=α g(x) − x h(x)g(x) − h(x)Iterativna funkcija (5) predstavlja iterativnu funkciju procesa (1). Dakle, iterativniproces (1) ima red konvergencije najmanje 2.Uzimajući α = 0, x 1 = β = 1 za funkciju f(x) = x 3 −3x 2 +4x −1, korišćenjem(1), dobijamok x k f(x k )1 1. 1.2 0.3333 0.03703 0.3176 0.0016.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!