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Ejercicios resueltos de Cálculo - Universidad de Málaga

Ejercicios resueltos de Cálculo - Universidad de Málaga

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<strong>Cálculo</strong> en varias variables 243<br />

Problema 122 Calcular las <strong>de</strong>rivadas parciales <strong>de</strong> la función dada respecto a cada variable:<br />

a) f(x,y,z) = z cosec(y/x)<br />

b) f(r,θ,z) =<br />

a) f(x,y,z) = z cosec (y/x) b) f(r,θ,z) =<br />

c) f(u,v,w) = (u 2 + v 2 + w 2 ) −1/2<br />

e) f(x,y,r,s) = sen 2x cosh 3r+senh3y cos 4s<br />

r(2 − cos 2θ)<br />

r 2 + z 2<br />

D1f(x,y,z) = y y y<br />

cos cosec2<br />

x2 x x<br />

D3f(x,y,z) = cos y<br />

x<br />

d) f(x,y,z) = (xy) z<br />

r(2 − cos 2θ)<br />

r 2 + z 2<br />

D2f(x,y,z) = − 1 y y<br />

cos cosec2<br />

x x x<br />

∂f<br />

∂r (r,θ,z) = (2 − cos 2θ)(r2 + z2 ) − 2r2 (2 − cos 2θ)<br />

(r2 + z2 ) 2 = (2 − cos 2θ)(z2 − r2 )<br />

(r2 + z2 ) 2<br />

∂f 2r<br />

(r,θ,z) =<br />

∂θ r2 sen 2θ<br />

+ z2 <strong>Ejercicios</strong> <strong>resueltos</strong> <strong>de</strong> <strong>Cálculo</strong>. c○Agustín Valver<strong>de</strong><br />

∂f<br />

− cos 2θ)<br />

(r,θ,z) = −2zr(2<br />

∂z (r2 + z2 ) 2

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