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Ejercicios resueltos de Cálculo - Universidad de Málaga

Ejercicios resueltos de Cálculo - Universidad de Málaga

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<strong>Cálculo</strong> en varias variables 244<br />

c) f(u,v,w) = (u 2 + v 2 + w 2 ) −1/2<br />

∂f<br />

∂u (u,v,w) = −u(u2 + v 2 + w 2 ) −3/2<br />

∂f<br />

∂w (u,v,w) = −w(u2 + v 2 + w 2 ) −3/2<br />

d) f(x,y,z) = (xy) z = e z log xy . El dominio <strong>de</strong> esta función es<br />

Las parciales son:<br />

∂f<br />

∂v (u,v,w) = −v(u2 + v 2 + w 2 ) −3/2<br />

Dom f = {(x,y,z)|xy > 0} ∪ {(x,y,z)|xy = 0,z > 0,z = 1}<br />

∂f<br />

log xy z<br />

(x,y,z) = ez<br />

∂x x<br />

e) f(x,y,r,s) = sen 2x cosh 3r + senh 3y cos 4s.<br />

∂f<br />

log xy z<br />

(x,y,z) = ez<br />

∂y y<br />

∂f<br />

(x,y,r,s) = 2cos 2xcosh 3r<br />

∂x<br />

∂f<br />

(x,y,r,s) = 3sen 2x senh3r<br />

∂r<br />

<strong>Ejercicios</strong> <strong>resueltos</strong> <strong>de</strong> <strong>Cálculo</strong>. c○Agustín Valver<strong>de</strong><br />

∂f<br />

∂z (x,y,z) = ez log xy log xy<br />

∂f<br />

(x,y,r,s) = 3cosh 3y cos 4s<br />

∂y<br />

∂f<br />

(x,y,r,s) = −4senh3y sen 4s<br />

∂s

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