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Ejercicios resueltos de Cálculo - Universidad de Málaga

Ejercicios resueltos de Cálculo - Universidad de Málaga

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Integración 432<br />

Problema 209 En los siguientes apartados hallar el área <strong>de</strong> la superficie obtenida al girar la curva dada alre<strong>de</strong>dor<br />

<strong>de</strong>l eje indicado:<br />

a) x = 2y <strong>de</strong>s<strong>de</strong> (2,1) a (6,3) alre<strong>de</strong>dor <strong>de</strong>l eje OX.<br />

b) y = x − 3 <strong>de</strong>s<strong>de</strong> x = 3 a x = 5 alre<strong>de</strong>dor <strong>de</strong> la recta x = −1.<br />

c) y = √ x <strong>de</strong>s<strong>de</strong> x = 1 a x = 3 alre<strong>de</strong>dor <strong>de</strong>l eje OX.<br />

d) x 2/3 + y 2/3 = a 2/3 para x ≥ 0 alre<strong>de</strong>dor <strong>de</strong>l eje OY .<br />

a) x = 2y <strong>de</strong>s<strong>de</strong> (2,1) a (6,3) alre<strong>de</strong>dor <strong>de</strong>l eje OX:<br />

S =<br />

6<br />

2<br />

2π x<br />

<br />

1 +<br />

2<br />

1<br />

√<br />

5<br />

dx =<br />

4 4 πx2<br />

6 = 8<br />

2<br />

√ 5π<br />

b) y = x −3 <strong>de</strong>s<strong>de</strong> x = 3 a x = 5 alre<strong>de</strong>dor <strong>de</strong> la recta x = −1; la superfice así generada coinci<strong>de</strong> con la generada<br />

al girar la curva y = (x − 1) − 3 <strong>de</strong>s<strong>de</strong> x = 3 + 1 a x = 5 + 1 alre<strong>de</strong>dor <strong>de</strong>l eje OY ; su área es:<br />

S =<br />

6<br />

<strong>Ejercicios</strong> <strong>resueltos</strong> <strong>de</strong> <strong>Cálculo</strong>. c○Agustín Valver<strong>de</strong><br />

4<br />

2π(x − 4) √ 1 + 1 dx = 4 √ 2

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