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KLASIˇCNA MEHANIKA - Studentske web stranice

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435<br />

iz čega zaključujemo da je<br />

δ(⃗r − ⃗r 0 ) = δ(r − r 0)<br />

r 2 0<br />

δ(θ − θ 0 )<br />

sin θ 0<br />

δ(ϕ − ϕ 0 ).<br />

U cilindričnom koordinatnom sustavu je<br />

iz čega slijedi<br />

∫ +∞<br />

0<br />

ρ dρ<br />

∫ 2π<br />

0<br />

dϕ<br />

∫ +∞<br />

−∞<br />

dz δ(⃗r − ⃗r 0 ) = 1,<br />

δ(⃗r − ⃗r 0 ) = δ(ρ − ρ 0)<br />

ρ 0<br />

δ(ϕ − ϕ 0 ) δ(z − z 0 ) .

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